OK, guys, I forgot to convert the amperage to 12 volts in the process of playing with the dog with one hand and trying to type and think with the other. Guess some of my common sense parameters went out the window too with accepting the answers, so I'll correct my homework errors below in red.
flapbreaker":1kmt6vgq said:
So how fast would a 2000 watt inverter drain a 110 amp hour battery?
Bob may well answer this too, but here goes!
First of all, you shouldn't drain the battery down more than 50%, so we go from 110 AH to 55 AH really available.
A 2000 watt inverter at full power is supplying 120 volts at 2000 watts, so it must be providing 16.6 amps in the process:
Amps X volts = watts, and 16.6 amps X 120 volts = 2000 watts
Now to provide 16.6 amps at 120 volts the battery must provide 10 times the amperage at 1/10 the voltage, so we draw 166 amps of current out of the battery instantaneously.
Now we have 55 AH in our battery to draw out, so knowing
amps X hours = AH , and hours = AH/amps, therefore
hours = 55 AH/166amps = .33 hours
So we have
.33 hours of run time for our inverter running at a full load 2000 watts on our 110 AH battery.
Furthermore, we need to subtract about 10% for the inefficiency (released as heat) of the inverter, so we get
0.3 hours of real run time, about
18 minutes or so from this rough calculation that doesn't consider everything, either.
Sorry if this is too detailed or wordy, but my background as a science teacher is hard to leave behind!
And now I've corrected my homework.
Do I have to stay for detention too?:unlove
Joe. :thup :teeth